Puts Out a peak of 56 Amps @ 5 volts, yet only draws 2 Amps @ 5 volts from the source!!! How is this possible you might ask? By the Law of Conservation of Energy, the reason is because the watt-seconds (joules) in and out are kept the same. If you want more current out than you draw in, then this means you’ll have to proportionally divide the time that it draws that peak current at. A capacitor is crucial because a low voltage battery certainly won’t be able to supply anywhere near the amount of current we’re trying to achieve here. A battery is made up of chemicals that have a much higher internal resistance than that of a simple capacitor made of just two plates of metal and a dialectic does.