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antonst
modified 12 years ago

Audio amplifier

3
42
187
02:40:30
published 12 years ago
antonst
12 years ago
Простой умзч hi-fi
thebugger
12 years ago
The signal is attenuating rather than amplifying?
hurz
12 years ago
60dB gain @ 10kHz is quite ok!
hurz
12 years ago
Both, go back and analyse this circuit again
hurz
12 years ago
See this Amplifier as black box with 2 input pins and 2 output pins. Start measurement and compare you will find out it has a gain of 60dB. Have fun
hurz
12 years ago
i dont know what you talking about, but I was talking about this amplifier.
hurz
12 years ago
Dear Pip, for your book of history, you claimed this is not at all an amplifier. What is the purpose of an amplifier? Gain power, right? Now for you a little equation P=(U*U)/R think about and come back with some useful commemts. Gracias
hurz
12 years ago
your claim is still " The signal is attenuating rather than amplifying? " pure situation for you. still waiting for your gain result....
hurz
12 years ago
Dont forget tomorrow is school again, try to learn something, and dont agree to your best internet friend "thebugger" if you think he is wrong. Try to think yourself, and be kind
hurz
12 years ago
I dont want to have stress with people, and it is realy getting boring now. I did already my calculation, belive it or not, i dont care. If you have different numbers and dont want them to publish keep them. But talking about "attenuation" as you agreed to thebugger, makes me LOL
hurz
12 years ago
now I am sure you learned something voltage is not the hole univers, there is even in your copied circuits current, and next time dont start to early to tell others there is no gain, lessons learned good night
hurz
12 years ago
Pipo, for you in slowmo, Measure the input power and output power, calculated the ratio and you will get about 1000 which you already know is 60dB. Got it?
hurz
12 years ago
So you agree my statement of 60dB gain is correct, or are you still bite in your fingers
hurz
12 years ago
And Pipo started the thread with, " Thebugger is right, no idea how you calculate 60db that's again of a 1000 times nothing like that here."
hurz
12 years ago
To refresh your memory, pipo pipo pipo .....
hurz
12 years ago
Please check your calculation again and be kind to us all and let us know what unit your result has. Its definitive not dB!
hurz
12 years ago
Probably you tried to calculate something like dBm. You realy dont know what dB means?
hurz
12 years ago
Who told you 20 log is just for voltages?
hurz
12 years ago
You mean dBA is sound pressure and 0dBm is 1mW at 50ohm?
hurz
12 years ago
You try to calculate an absolut value, but this is not called dB.
hurz
12 years ago
An absolut value must have a unit like dBuV or something
hurz
12 years ago
Again, and the result of your equation has the UNIT dB? I guess no
hurz
12 years ago
Ok
hurz
12 years ago
You said gain is: 10*log(U*I) ?
hurz
12 years ago
I like dB a lot, because its an easy thing to calculate with.
hurz
12 years ago
Let gain be G, you said G = 10 log (U * I) ?
hurz
12 years ago
Wasn't it you who want me to start math expressions?
hurz
12 years ago
Please let me know what Ap Av and Ai is I just have to guess
hurz
12 years ago
Did you mean Avarage Power with Av?
hurz
12 years ago
Av Average voltage?
hurz
12 years ago
Your expression makes no sense.
hurz
12 years ago
To have a gain you have to compare 2 things and i dont see this in your expression
hurz
12 years ago
You have to have a reference point, audio input, and an output value
hurz
12 years ago
Both points from the same unit
hurz
12 years ago
In our case input current 200uA output current 200mA peak!
hurz
12 years ago
20*log(200mA/200uA) = 60dB
hurz
12 years ago
And by magic there is just "dB" and no dBW or something you tried to calcuate
hurz
12 years ago
Why is it a problem for you to answer simple questions?
hurz
12 years ago
So math is not yours, right?
hurz
12 years ago
Sorry if i made to much pressure one you
antonst
12 years ago
This production scheme ussr 1975
hurz
12 years ago
Спасибо

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