120vRMS AC to 5v 2A DC

208

02:30:35

Its a somewhat effeincent linear regulator. Vec@2A = 5.63 - 5.01 = 0.62v
Pbjt = IV = 2*0.62= 1.24 W
Pload = 2*5.01 = 10 W
Pbjt + Pload =~Pin 
100*(Pout/Pin) = 100* (10 / 11.24) = 89% eff
89% @ 2A effeincent sound about right?

Efficency is inversely proportional to the load resistance. In other words, if one goes up, the other goes down.

published 10 years ago

yitriq

10 years ago

altairiii

10 years ago

Pbjt

hurz

10 years ago

The input voltage of this regulator is to close to the output voltage and brings up the question why in this case a regulator anyway? Just use a switch and forward in to out with 100% efficiency. To keep the out voltage ripplefree you also need an extreme fat cap 100mF just for 2A 5V out. A better thumb of rule to make some calculation is double the input voltage to 10V in unloaded and see how the efficiency is. Keep it up!

GingerKing

10 years ago

Hey hurz, the input voltage is only close to the output voltage when the load is drawing more than an amp. How can I use a switch to achieve 100%? Doubling the input voltage would ruin the efficency of my design. My goal is to one day make a power supply. Variable Volatge/Current control with at least 80% efficency. SMPS was a fail :( Got any circuits you can point me to?

arjunkumarg

10 years ago

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