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modified 2 years ago

Full-Bridge Rectifier Smoother

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05:21:58
Full-Bridge Rectifier. 9V 60Hz source. We want a smoother output. A capacitor in parallel with the load helps that. The capacitor is chosen so that R_Load x C >> 1/f, or C >> 1/R_Load x f = 16.6 μF here. We select a value 10x larger, so 170μF. Increasing the capacitance (e.g up to 1mF) will produce an even smoother output. Follows Full Bridge Rectifier: https://everycircuit.com/circuit/6073208297750528 The ripple voltage can be estimated as: ΔV = I_Load / 2fC Here, I_Load = 7.2 mA more or less, f = 60Hz and C = 170μF, so ΔV = 0.35V. The voltmeter says Min/Max are 7.02 and 7.3V here, so ΔV = 0.28V. Fair enough.
published 2 years ago

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