M

144

02:03:12

What did I do wrong.

published 9 years ago

mmarko

9 years ago

Use a pulse signal,and set the relays to turn on and off to a voltage within the signal range

pedroretro

9 years ago

All.

justinmh

9 years ago

Set the power supply to 5 volts, and flip it. Put a 200 ohm resistor in series with the light. Then wire the relay so when it is energized the power flows from the back of the main switch to the side that flips, then connect that side to the light and resistor. The way you have it now current will never flow through the light, as it has no path if the relay were to energize.

2ctiby

9 years ago

Here http://everycircuit.com/circuit/5320991709855744

Ajinkya_Mahajan

9 years ago

The Current always follows the least opposition path

hurz

9 years ago

Full stop. Nobody on earth can know what you expect as working circuit with this schematic. No one! Whats needed is at least a little description/specification.

rajnishthegreat

9 years ago

Its a short-circuit.

Bushmills

9 years ago

It is a flame retardant properties tester

maxmax_66

9 years ago

I'm pretty sure it's a battery operated continuous relay bypass widget with optional decorative bulb.

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