Multiple Transformer Math Question Version 2

V = IR so I = V/R then since R is just 1 unit in all cases here, then amps current is directly proportional to V. The V output in all four circuits here is basically determined by proportion of secondary to primary windings, and since 4 windings are in parallel, then they are in effect 4x fewer windings than if they were joined in series. Hence with fewer effective primary windings (as in schematic 2), the ratio is increased and so the V out is 4x increased (max values), and likewise for the directly proportional current there. So the total power seen in schematic 2 is 4x4 max greater than schematic 1 on the far left. This is shown by EC there. (4mA x 4V = 16 mW for schematic2 cp 1mW for schematic1 at far left). There is no magic supply....EC source just supplies the appropriate current and voltage where necessary to fit the mathematical model. (Other effects would need further consideration such as Eddy currents, rms etc).

Thank You. Not looking for magic, just a mention that it is correct"ish" so that the younger generation of interested folks can have it in front of them as well.