what problem it is

115

02:15:07

please help,the light can not turn on

published 12 years ago

adrien1018

12 years ago

Adjust current to 20mA.

LeeXabyz

12 years ago

Or remove the current source entirely, and change total resistance to 500-1k ohm

justinmcg67

12 years ago

Remove at least 4 resistors. Remove the current source. No need for inductors.

APO69

12 years ago

Think only in watts. W= V*I If I = 1mA, V ( lamp) = 1'5V => W (lamp) = 1'5 mW. Put this value in lamp tag or change others values to make correct W = V*I Of course, you can play with this values. Only one condition! , these values must do true the MAXIMUM W =V*I

APO69

12 years ago

Examples that works: I = 0.23mA, W = 45 mW => V = 195'6 V ..... another V = 0.85 V, W = 0'1 W => I = 117 mA... so on.

APO69

12 years ago

Pay attention that 0'23mA are equal to 230 micro Amperes...

Jrc

12 years ago

Battery on right is reversed. Increase current at output of op amp.

mocito

12 years ago

You need to increase the current of the current supply after the am pop or remove it. Since you have 1mA on that current source, it will impose 1 mA on that line (lamps will only have one 1mA and it isn't enough for them to light up). You need to increase that current according to the power of the lamps or remove the current source.

APO69

12 years ago

Think in watts, think in watts... Think about this!. We can change a lot of components to make it works but any way the power will be who determines if the lamp is going to light or not. If current is 1mA and V lamp is 1’5V, the power lamp should be 1’5mW. But we could also adapt the power to the circuit by making I=20mA, because 30mW / 1’5V = 20mA. Or we could also adapt it by making V lamp = 30V, because 30mW / 1mA = 30V… As you see, the power is what matters. Without add or remove components we can get lamps lit. Watts, watts and watts.

APO69

12 years ago

This happens because when you modify the two values, voltage or power of the lamp, you are changing the value of its resistance. W = V * I = R * I^2 = V^2 / R => R = W / R^2 or R = V^2 / W

APO69

12 years ago

And... so current is constant, in this circuit, everything depends from it.

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